[BREAST FEEDING AS PREVENTIVE FACTOR FOR OSTEOPOROSIS IN ADULT WOMEN].

INTRODUCTION

breastfeeding is considered protective of osteoporosis, by endocrine changes, such as the rise of intestinal absorption of calcium and the renal conservation of the same, however, other studies demonstrate that with more one child they present a loss of bone mineral density (BMD) (2-9%).

OBJECTIVE

to determine if breastfeeding is a protective factor or a risk in osteoporosis in Queretaro's women.

SUBJECTS AND

METHODS

retrospective study of cases y controls. 114 women from 35 to 60 years divided in control group (without breastfeeding) and women those that breastfeed. Diagnostic of BMD by bone densitometry of two regions: Hip (femur) and lumbar. Clinical history applies. Criteria of inclusion: age 35-60 years. Criteria of exclusion: consumption: calcium, hormonal replacement therapy, treatment for osteoporosis: breastfeeding or pregnant. It will provide evidence of a central trend, T couplet, correlations, Chi2 y profitable reasons.

RESULTS

breastfeeding was found to have a protection factor con 0.903 OR (0.768-1.006). Inverse correlation of BMI/BMD in hip and lumbar regions, in women that did not breast contrary to those that did breastfeed. In both groups in was determined a greater age of pregnancy with greater BMD in the hips and greater size of the child, only in women that breastfeed. Being the obesity factor of the women that breastfeed. However, a inverse correlation was found among Age/BMD in three regions from women that breasted, contrary to those that did not breastfeed specifically in the BMD lumbar.

CONCLUSION

breastfeeding is beneficial for the mother as it is a protective factor against osteoporosis, as long as it holds the first 6 months and for newborn optimal linear growth.